select o.order_num, sum (i.total_price) price,
	paid_date - order_date span
	from orders o, items i
	where o.order_date > "01/01/89"
		and o.customer_num > 110
		and o.order_num = i.order_num
	group by 1, 3
	having count (*) < 5
	order by 3
	into temp temptab1;